NAME
Crypt::Skip32 - 32-bit block cipher based on Skipjack
SYNOPSIS
use Crypt::Skip32;
my $cipher = new Crypt::Skip32 $key;
my $ciphertext = $cipher->encrypt($plaintext);
my $plaintext = $cipher->decrypt($ciphertext);
my $blocksize = $cipher->blocksize;
my $keysize = $cipher->keysize;
DESCRIPTION
SKIP32 is a 80-bit key, 32-bit block cipher based on Skipjack. The Perl code for the algorithm is a direct translation from C to Perl of skip32.c by Greg Rose found here:
http://www.qualcomm.com.au/PublicationsDocs/skip32.c
This cipher can be handy for scrambling small (32-bit) values when you would like to obscure them while keeping the encrypted output size small (also only 32 bits).
One example where Crypt::Skip32 has been useful: You have numeric database record ids which increment sequentially. You would like to use them in URLs, but you don't want to make it obvious how many X's you have in the database by putting the ids directly in the URLs.
You can use Crypt::Skip32 to scramble ids and put the resulting 32-bit value in URLs (perhaps as 8 hex digits or some other shorter encoding). When a user requests a URL, you can unscramble the id to retrieve the object from the database.
Warning: A 32-bit value can only go a little over 4 billion (American). Plan ahead if what you need to encrypt might eventually go over this limit.
FUNCTIONS
- new
-
my $cipher = new Crypt::Skip32 $key;
Creates a new Crypt::Skip32 block cipher object, using $key, where $key is a key of
keysize
bytes (10). - encrypt
-
my $ciphertext = $cipher->encrypt($plaintext);
Encrypt $plaintext and return the $ciphertext. The $plaintext must be of
blocksize
bytes (4).See the EXAMPLE below for hints on how to take a plain integer, encrypt it, and encode it for use in URLs and other non-binary formats.
- decrypt
-
my $plaintext = $cipher->decrypt($ciphertext);
Decrypt $ciphertext and return the $plaintext. The $ciphertext must be of
blocksize
bytes (4). - blocksize
-
my $blocksize = $cipher->blocksize; my $blocksize = Crypt::Skip32->blocksize;
Returns the size (in bytes) of the block cipher. This is always 4 bytes (for 32 bits).
- keysize
-
my $keysize = $cipher->keysize; my $keysize = Crypt::Skip32->keysize;
Returns the size (in bytes) of the key. This is always 10 bytes (for 80 bits).
NOTES
If Crypt::Skip32::XS is installed, this module will use it and the constructor will return an object of that type, though the interface is identical. You can stick with the pure Perl version by setting the CRYPT_SKIP32_PP environment variable before using this module.
If reporting a bug, please try to determine (if possible) if it is this module or the XS one, and report it to the corresponding maintainer.
EXAMPLE
This sample code demonstrates how Crypt::Skip32 can be used to encrypt unsigned integers and encode them for use in web URLs, form values, and other places where short encrypted text might be useful.
use Crypt::Skip32;
# Create a cipher. Change the long hex string to your secret key.
my $key = pack("H20", "112233445566778899AA");
my $cipher = new Crypt::Skip32 $key; # Always 10 bytes!
# Encrypt an unsigned integer (under 2^32) into an 8-digit hex string.
my $number = 3493209676;
my $plaintext = pack("N", $number);
my $ciphertext = $cipher->encrypt($plaintext); # Always 4 bytes!
my $cipherhex = unpack("H8", $ciphertext);
print "$number encrypted and converted to hex: $cipherhex\n";
# Decrypt an encrypted, hexified unsigned integer.
my $ciphertext2 = pack("H8", $cipherhex);
my $plaintext2 = $cipher->decrypt($ciphertext); # Always 4 bytes!
my $number2 = unpack("N", $plaintext2);
print "$cipherhex converted back and decrypted: $number2\n";
The above code generates the output:
3493209676 encrypted and converted to hex: 6da27100
6da27100 converted back and decrypted: 3493209676
CAVEATS
This initial alpha Perl implementation of Crypt::Skip32 has not been extentively reviewed by cryptographic experts, nor has it been tested extensively on many different platforms. It is recommended that this code not be used for applications which require a high level of security.
Reviewers and testers welcomed.
Though this module has been coded to follow a Crypt::CBC usable interface, it is not intended for use in encrypting long chunks of text. For those purposes, it is suggested you use another high quality, proven cipher with a longer block size.
SEE ALSO
The original SKIP32 implementation in C by Greg Rose: http://www.qualcomm.com.au/PublicationsDocs/skip32.c
The 80-bit key, 64-bit block Skipjack cipher created by the NSA (Perl code maintained by Julius C. Duque): Crypt::Skipjack
Crypt::Skip32::XS
AUTHOR
Perl code maintained by Eric Hammond <eric-cpan@thinksome.com> http://www.anvilon.com
Original SKIP32 C code written 1999-04-27 by Greg Rose, based on an implementation of the Skipjack algorithm written by Panu Rissanen.
COPYRIGHT AND LICENSE
Copyright (C) 2007-2008 Eric Hammond
This library is free software; you can redistribute it and/or modify it under the same terms as Perl itself, either Perl version 5.8.8 or, at your option, any later version of Perl 5 you may have available.
The original C version of SKIP32 by Greg Rose (see below) is explicitly "not copyright, no rights reserved". Even so, permission was requested and granted to make a Perl version available on the CPAN.
ORIGINAL C SOURCE
/*
SKIP32 -- 32 bit block cipher based on SKIPJACK.
Written by Greg Rose, QUALCOMM Australia, 1999/04/27.
In common: F-table, G-permutation, key schedule.
Different: 24 round feistel structure.
Based on: Unoptimized test implementation of SKIPJACK algorithm
Panu Rissanen <bande@lut.fi>
SKIPJACK and KEA Algorithm Specifications
Version 2.0
29 May 1998
Not copyright, no rights reserved.
*/
typedef unsigned char BYTE; /* 8 bits */
typedef unsigned short WORD; /* 16 bits */
const BYTE ftable[256] = {
0xa3,0xd7,0x09,0x83,0xf8,0x48,0xf6,0xf4,0xb3,0x21,0x15,0x78,0x99,0xb1,0xaf,0xf9,
0xe7,0x2d,0x4d,0x8a,0xce,0x4c,0xca,0x2e,0x52,0x95,0xd9,0x1e,0x4e,0x38,0x44,0x28,
0x0a,0xdf,0x02,0xa0,0x17,0xf1,0x60,0x68,0x12,0xb7,0x7a,0xc3,0xe9,0xfa,0x3d,0x53,
0x96,0x84,0x6b,0xba,0xf2,0x63,0x9a,0x19,0x7c,0xae,0xe5,0xf5,0xf7,0x16,0x6a,0xa2,
0x39,0xb6,0x7b,0x0f,0xc1,0x93,0x81,0x1b,0xee,0xb4,0x1a,0xea,0xd0,0x91,0x2f,0xb8,
0x55,0xb9,0xda,0x85,0x3f,0x41,0xbf,0xe0,0x5a,0x58,0x80,0x5f,0x66,0x0b,0xd8,0x90,
0x35,0xd5,0xc0,0xa7,0x33,0x06,0x65,0x69,0x45,0x00,0x94,0x56,0x6d,0x98,0x9b,0x76,
0x97,0xfc,0xb2,0xc2,0xb0,0xfe,0xdb,0x20,0xe1,0xeb,0xd6,0xe4,0xdd,0x47,0x4a,0x1d,
0x42,0xed,0x9e,0x6e,0x49,0x3c,0xcd,0x43,0x27,0xd2,0x07,0xd4,0xde,0xc7,0x67,0x18,
0x89,0xcb,0x30,0x1f,0x8d,0xc6,0x8f,0xaa,0xc8,0x74,0xdc,0xc9,0x5d,0x5c,0x31,0xa4,
0x70,0x88,0x61,0x2c,0x9f,0x0d,0x2b,0x87,0x50,0x82,0x54,0x64,0x26,0x7d,0x03,0x40,
0x34,0x4b,0x1c,0x73,0xd1,0xc4,0xfd,0x3b,0xcc,0xfb,0x7f,0xab,0xe6,0x3e,0x5b,0xa5,
0xad,0x04,0x23,0x9c,0x14,0x51,0x22,0xf0,0x29,0x79,0x71,0x7e,0xff,0x8c,0x0e,0xe2,
0x0c,0xef,0xbc,0x72,0x75,0x6f,0x37,0xa1,0xec,0xd3,0x8e,0x62,0x8b,0x86,0x10,0xe8,
0x08,0x77,0x11,0xbe,0x92,0x4f,0x24,0xc5,0x32,0x36,0x9d,0xcf,0xf3,0xa6,0xbb,0xac,
0x5e,0x6c,0xa9,0x13,0x57,0x25,0xb5,0xe3,0xbd,0xa8,0x3a,0x01,0x05,0x59,0x2a,0x46
};
WORD
g(BYTE *key, int k, WORD w)
{
BYTE g1, g2, g3, g4, g5, g6;
g1 = (w>>8)&0xff;
g2 = w&0xff;
g3 = ftable[g2 ^ key[(4*k)%10]] ^ g1;
g4 = ftable[g3 ^ key[(4*k+1)%10]] ^ g2;
g5 = ftable[g4 ^ key[(4*k+2)%10]] ^ g3;
g6 = ftable[g5 ^ key[(4*k+3)%10]] ^ g4;
return ((g5<<8) + g6);
}
void
skip32(BYTE key[10], BYTE buf[4], int encrypt)
{
int k; /* round number */
int i; /* round counter */
int kstep;
WORD wl, wr;
/* sort out direction */
if (encrypt)
kstep = 1, k = 0;
else
kstep = -1, k = 23;
/* pack into words */
wl = (buf[0] << 8) + buf[1];
wr = (buf[2] << 8) + buf[3];
/* 24 feistel rounds, doubled up */
for (i = 0; i < 24/2; ++i) {
wr ^= g(key, k, wl) ^ k;
k += kstep;
wl ^= g(key, k, wr) ^ k;
k += kstep;
}
/* implicitly swap halves while unpacking */
buf[0] = wr >> 8; buf[1] = wr & 0xFF;
buf[2] = wl >> 8; buf[3] = wl & 0xFF;
}
#include <stdio.h>
int main(int ac, char *av[])
{
BYTE in[4] = { 0x33,0x22,0x11,0x00 };
BYTE key[10] = { 0x00,0x99,0x88,0x77,0x66,0x55,0x44,0x33,0x22,0x11 };
int i, encrypt;
int bt;
if (ac == 1) {
skip32(key, in, 1);
printf("%02x%02x%02x%02x\n", in[0], in[1], in[2], in[3]);
if (in[0] != 0x81 || in[1] != 0x9d || in[2] != 0x5f || in[3] != 0x1f) {
printf("819d5f1f is the answer! Didn't encrypt correctly!\n");
return 1;
}
skip32(key, in, 0);
if (in[0] != 0x33 || in[1] != 0x22 || in[2] != 0x11 || in[3] != 0x00) {
printf("%02x%02x%02x%02x\n", in[0], in[1], in[2], in[3]);
printf("33221100 is the answer! Didn't decrypt correctly!\n");
return 1;
}
}
else if (ac != 4) {
fprintf(stderr, "usage: %s e/d kkkkkkkkkkkkkkkkkkkk dddddddd\n", av[0]);
return 1;
}
else {
encrypt = av[1][0] == 'e';
for (i = 0; i < 10; ++i) {
sscanf(&av[2][i*2], "%02x", &bt);
key[i] = bt;
}
for (i = 0; i < 4; ++i) {
sscanf(&av[3][i*2], "%02x", &bt);
in[i] = bt;
}
skip32(key, in, encrypt);
printf("%02x%02x%02x%02x\n", in[0], in[1], in[2], in[3]);
}
return 0;
}